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Hey all,

1996 mustang, running MM c/c plates @ max. caster & -2deg camber...

Say the steering is at 1/2 lock, aprox how much more neg camber is the extra caster adding into the equation? Is there a formula out there?...

Thanks!
 

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If you have 0 caster you have 0 camber gain, if you 90 degree caster you have same amount camber in degrees as wheel turn in degrees. One degree wheel turn one degree camber.

Wheels usually turns about 25 - 28 degrees left and right from driving straight. From there you can create a formula for camber gain to 1 degree of caster:

1/90 * caster (degrees) * turning angle (degrees from wheels)

So if you have -2 degrees caster when you turn your wheels for example 10 degrees you gain:

1/90 * -2 * 10 = -0,22 degrees of camber

I just made this up and it may not be correct and i'm not sure if the camber gain is linear to wheels turn. But it makes sence to me so it might work.;)
 
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